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3. A 5kg ball on the end of a string is whirled at
a constant speed of 1 m s'in a horizontal circle
of radius 5 m. What is the work done by the
centripetal force during one revolution ?
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Answer:
Mass of the body(M) = 5 Kg.
Velocity (v) = 1.0 m/s.
Radius of circle (r) = 5m.
Finding the Centripetal force.
Substituting the values,
Now,
After one revolution the Displacement will be zero.
and the angle made by the force and displacement is 90°.
As the Centripetal force is acting inwards and displacement perpendicular to it.
Now,
Work done formula,
Substituting the values ,
As cos90° = 0.
So, the work done by the Centripetal force is "Zero".
Explanation:
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