Physics, asked by sachusanu05, 11 months ago

3. A battery of 10 volt carries 20,000 C of charge through a resistance of 20 Ω. The work done in 10 seconds is (a) 2 × 103 joule (b) 2 × 105joule (c) 2 × 104 joule (d) 2 × 102 joule

Answers

Answered by XxMissPaglixX

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Question - 7. A battery of 10 volt carries 20,000 C of charge through a resistance of 20 ohm

The work done in 10 seconds is

(a) 2 x 10^2 joule

(b) 2 x 10^3 joule

(d) 2 x 10^5 joule

Answer -

Work done will be - (d) 2 x 10^5 joule

Work done by the battery is calculated by the formula -

P = w/t

Here, p represents power, w denotes work and t is for time.

Power in terms of voltage and current is calculated by the formula

- P = V*I

Current, when the charge is given, is calculated by the formula -

Q = I*t

I denote current, t is for time, and v represents voltage. Q is for a charge.

Now, putting given values in equation -

I = Q/t

I = 20,000/10

I = 2000 ampere.

P = 10*2000

Thus power will be 20,000 W of J/s

Now, work done will be -

W = 20,000*10

W = 2*10^5 J

Thus, work done by the battery will be 2*10^5 J.

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Answered by adityachoudhary2956

131

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Work done will be - (d) 2 x 10^5 joule

Work done by the battery is calculated by the formula -

P = w/t

Here, p represents power, w denotes work and t is for time.

Power in terms of voltage and current is calculated by the formula

- P = V*I

Current, when the charge is given, is calculated by the formula -

Q = I*t

I denote current, t is for time, and v represents voltage. Q is for a charge.

Now, putting given values in equation -

I = Q/t

I = 20,000/10

I = 2000 ampere.

P = 10*2000

Thus power will be 20,000 W of J/s

Now, work done will be -

W = 20,000*10

W = 2*10^5 J

Thus, work done by the battery will be 2*10^5 J.

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