(3) A body moves with a uniform acceleration of 2 m/s. If the initial velocity of the
body is 10 m/s, find the velocity of the body after 2 seconds.
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Answered by
2
u=10m/s
a=2m/s^2
t=2 seconds
v=u+at
v=10+2×2
v=14m/s
Answered by
10
Answer:
Given :
- Acceleration of the body = 2 m/s².
- Initial velocity of the body = 10 m/s.
- Time = 2 s.
To Find :
- Final velocity of the body = ?
Solution :
Using first equation of motion :
⇒ v = u + at
⇒ v = 10 + 2*2
⇒ v = 10 + 4
⇒ v = 14 m/s
Hence, the final velocity of the body after 2 seconds are : 14 m/s.
Important Formulas :
- v = u + at
- s = ut + ½at²
- v² - u² = 2as
- Average velocity = ∆x/∆t
- Average speed = Total path/Total time
- Instantaneous velocity = dx/dt
- Average acceleration = ∆v/∆t
- Instantaneous acceleration = dv/dt
- ∆x = x2 - x1 (Displacement)
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