Question

3. A body of mass 1 kg is moving with a speed of 10 ms on a level surface. It comes to rest after
travelling a distance of 5 m.
Now answer the following questions :
(1) Name the type of energy possessed by the body before it comes to rest.
(in) What is the amount of work done on the body ?
(ii) is work done positive or negative ?
(iv) Calculate the acceleration of the body.
in numbere
are hased on the table given below and answer the questions​

Answer 1

(i) kinetic energy
(ii) F = ma
= -10 N
(iii) negative

Answer 2

(a). The kinetic energy is 50 J.

(b). The work done on the body is -50 J.

(c). The work done is negative.

(d). The acceleration is 10 m/s².

Explanation:

Given that,

Mass of body = 1 kg

Speed = 10 m/s

Distance = 5 m

(a) We need to calculate the kinetic energy

Using formula of kinetic energy

$K.E=\dfrac{1}{2}mv^2$

Where, m = mass of object

v = velocity

Put the value into the formula

$K.E=\dfrac{1}{2}\times1\times(10)^2$

$K.E=50\ J$

The kinetic energy is 50 J.

We need to calculate the acceleration

Using equation of motion

$v^2=u^2+2as$

Put the value into the formula

$0=10^2+2\times a\times 5$

$a=-10\ m/s^2$

The acceleration is negative.

(b). We need to calculate the work done on the body

Using formula of force

$W=F\times d$

$W=ma\times d$

Where, F = force

d = distance

Put the value into the formula

$W=1\times(-10)\times5$

$W=-50\ J$

(c). The work done is negative.

(d). We need to calculate the acceleration

Using equation of motion

$v^2=u^2+2as$

Put the value into the formula

$0=10^2+2\times a\times 5$

$a=-10\ m/s^2$

Hence, (a). The kinetic energy is 50 J.

(b). The work done on the body is -50 J.

(c). The work done is negative.

(d). The acceleration is 10 m/s².

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Topic : work done

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