Question

3. A box contains 3 red balls. 7 black balls and 5 green balls. One ball is drawn from the bene
at random. Find the probability of drawing a:
(a) green ball
(b) black or red ball (c) ball that is not black​

Answer 1

Answer:

1. probability of green ball = 5/15 or 1/3
2. probability of black or red ball = 10/15 or 2/3
3. probability of not black ball = 8/15

Step-by-step explanation:

Thank you

Answer 2

Answer:

(a). $\frac{1}{3}$ ; (b). $\frac{2}{3}$ (c). $\frac{8}{15}$

Step-by-step explanation:

Total outcome is 15

(a). Favorable outcome 5

Probability of drawing a green ball is $\frac{5}{15}$ = $\frac{1}{3}$

(b). Favorable outcome 7 + 3 = 10  

Probability of drawing a black or red ball is $\frac{10}{15}$ = $\frac{2}{3}$

(c). Favorable outcome 15 - 7 = 8  

Probability of drawing a ball that is not black​ is $\frac{8}{15}$