Question

3. A box that is initially at rest is pushed for 5.5 seconds and has a final
momentum of 628 kg m/s.
(a) What is the change in momentum of the box?
(b) What is the net force on the box?​

Answer 1

Answer:

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Answer 2

Answer:

Answer-

( identity : (a-b)² = a²-2ab +b²)

= {(2x - 5y)}^{2}=(2x−5y)

2

= {(2x)}^{2} - 2(2x)(5y) + {(5y)}^{2}=(2x)

2

−2(2x)(5y)+(5y)

2

= 4 {x}^{2} - 20xy + 25 {y}^{2}=4x

2

−20xy+25y

2