Math, asked by atharvachaudhari81, 12 days ago

(3)
Two cross roads 2.5 m wide have been constructed in the middle of a garden
crossing each other at right angles, running parallel to the sides of the garden 35 m
long and 20 m wide. Find the cost of constructing the roads at the rate of 100 per
sq.m.​

Answers

Answered by introtube36
1

Answer:

3125 rupees

Step-by-step explanation:

Area of Road along length =

(35×2.5) = 87.5m

Area of Road along breadth=

(20×2.5) = 50.0m

Area of common portion =

(2.5×2.5) = 6.25m

Therefore, Area of road =

(Area of Road along breadth + Area of road along length) - common portion =

(87.5+50)-6.25=

37.6-6.25=

31.25

Hence, cost of road at 100 per sq.m. =

(31.25×100)=

3125 rupees

I hope it helps.

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