Question

3) A bus accelerates uniformly from 54km/h to 72km/h in 10s. Calculate: (i) the

acceleration (ii) the distance covered by the bus in that time.​

Answer 1

Answer:

Initial velocity, u = 72 km/h = 72 (5/18) m/s = 20 m/s

Final velocity, v = 54 km/h = 54 (5/18) m/s = 15 m/s

Time, t = 10 seconds

Distance traveled by the bus

v² = u² + 2aS

20² = 15² + 2 × 0.5 × S

400 = 225 + 1×S

400 – 225 = S

S = 175 m

Accelaration:

a = (v – u)/t

a = (20-15)/10

= 0.5 m/s²

Explanation:

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