Question

3.
A car moves with a constant velocity of 10 m/s for 10 sec along
a straight trace, then it moves with uniform acceleration of
2 m/s2 for 5 second. Find the total displacement and
velocity at the end of the 5th second of acceleration​

Answer 1

For the current problem, it is good ignore that the car is moving for 10s at 10m/s.

Initial Velocity 10m/s, Acceleration 2m/s/s.

Hence, Distance Covered During First 5 seconds of Acceleration = (Initial Velocity)x(Time) + (Acceleration)x(Time)x(Time)/2

= (10)x(5)m + (2)x(5)x(5)/2 m = 50m + 25 m = 75m

Velocity at end of 5th second = (Initial Velocity) + (Acceleration)x(Time)

= 10m/s + 2x5 m/s = 20m/s

Total Distance Covered = Distance Covered During First 10 seconds + Distance Covered During First 5 seconds of Acceleration

= 10x10m + 75m = 100 + 75m = 175m