Question

3. A cell of en
connected in
all of e.m.f. 1.8 V and internal resistance 20 is
sted in series with an ammeter of resistance
and a resistor of 4.5 12 as shown in Fig. 8.43.
1.8 V
0.7 12 and a resistore
222
4.5
2
0.7 12
Fig. 8.43
(a) What would be the reading of the ammeter ?
(b) What is the potential difference across the
terminals of the cell ?​

Answer 1

Answer: current in circuit = reading of ammeter = voltage applied/total resistance = 1.8/(2+0.7+4.5) = 0.25A

Potential difference across the terminals of cell = V-IR = 2-0.25*2= 1.5V