Question

3. A circle fits perfectly in a square of side 28 cm. Find the area of remaining part of the
square outside the circle.
​

Answer 1

Step-by-step explanation:

Perimeter of square = circumference of circle

a

2

=2πr

28×28=2×

7

22

×r

784=

7

44

×r

44

784×7

=r

r=124.72

Area of circle =πr

2

=

7

22

×(124.72)²

=48887.38 cm²

Answer 2

Answer:

168cm^2

Step-by-step explanation:

Area of the remaining part=

Area of the square -Area of the circle

Area of the square=side*side = 28*28= 784 cm^2

Area of the circle= πr^2= 22/7*14*14=616cm^2

(here r= 14 since r=28/2 )

Hence,

Area of the remaining part = 784-616= 168cm^2