Question

3. A circus artist is climbing a 20 m long rope, which
is tightly stretched and tied from the top of a
vertical pole. Find the height of the pole if
the angle made by the rope with the ground level
is 30
​

Answer 1

Answer:

is given that, Length of rope = 20 m Hence, AC = 20m Also, angle made by rope with the ground level = 30° Hence, ∠ACB=30° We need to find height of pole i.e. AB Since the pole is vertical, ∠ ABC = 90° In right triangle ABC sin C = ( " " " " )/ sin 30°= / (1 )/2 = /20 1/2×20 = AB ...

Answer 2

Answer:

let AB the height of tower

and AC the lenght of rope :20m

now in rt triangle ABC

Sin30 : AB/ A.C.

sin 1/2: 20/A.C.

AC: 10m

since,height of tower =10 m