Question

3 A driver accelerates his car
first at the date of 4ms
and then rate of 8ms calcutale
the ratio of forces, by the
engins​

Answer 1

Answer:

In the first case , F = m x a = 4mn

In the second case , F = m x a = 8mn

So , the Ratios of force exerted are = 4 : 8 = 2 : 4

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Answer 2

Answer:  1:2

Explanation:

Given that,

first— he accelerates at 4m/s

next at — 8 m/s ratio of the two is

4:8 = 2:4 = 1:2