3.
A
In the adjoining figure, AB CD and AB = CD. Prove that:
(a) AAOBADOC
(b) OA = OD
(c) OB =OC
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GIVEN:
- Let ABCD is a parallelogram
- AC and BD are two diagonals
- AD=BC
RTP:
- AC=BD ( sides of llgm =)
- AO=OD (llgm diagonal object each other)
- OB=OC (Object each other)
By sss congruence rule:
- Therefore triangle AOB congruent DOC
- AOB=DOC(by sss rule)
Mark dear (brainliest)❤
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Answer:
(a)
this is your ans
sorry I don't know the rest
but I hope it helps you
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