Question

3. A load of 50 kg is pulled upward by 5 m. The work done by the external force is (g = 10 m/s2) *
(1 Point)​

Answer 1

Explanation:

Work done=force×distance

w=50×10×5(10 is the acceleration due to gravity)

so workdone=2500joule

Answer 2

Answer:

2500 J

Explanation:

When the object is lifted upward, there is some potential energy there...
We Know That: potential energy = Mass×Gravity×Height

=> Work = 50kg×10m/s×5m

=> work = 2500J