Question

3. A motor cycle moving with a speed of 5m/s if applied an acceleration of 0.2m/s2. Calculate the speed of motorcycle after 10 seconds, and the distance travelled by it in this time.

Answer 1

v=?
u=5m/s
a=0.2ms²
t=10
v=u+at
v= 5+0.2x10
v= 7
speed after 10s = 7 m/s

s=ut+1/2at²
s= 5x10+0.2x10²/2
s=50+10
s= 60m
distance= 60m

Answer 2

u=5m/s, a=0.2m/s^2, t=10s. (given)

v=u+at

v=5+.2×10

v= 5+2

v= 7m/s

v^2=u^2+2as

(7)^2 = (5)^2 + 2 ×. 2×s

49 = 25  + .4s

49 - 25 = .4s

24 = .4s

s=24/.4

s=240/4

s= 60 m

distance travelled = 60 m