3. A motor cycle moving with a speed of 5m/s if applied an acceleration of 0.2m/s2. Calculate the speed of motorcycle after 10 seconds, and the distance travelled by it in this time.
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u=5m/s, a=0.2m/s^2, t=10s. (given)
v=u+at
v=5+.2×10
v= 5+2
v= 7m/s
v^2=u^2+2as
(7)^2 = (5)^2 + 2 ×. 2×s
49 = 25 + .4s
49 - 25 = .4s
24 = .4s
s=24/.4
s=240/4
s= 60 m
distance travelled = 60 m
v=u+at
v=5+.2×10
v= 5+2
v= 7m/s
v^2=u^2+2as
(7)^2 = (5)^2 + 2 ×. 2×s
49 = 25 + .4s
49 - 25 = .4s
24 = .4s
s=24/.4
s=240/4
s= 60 m
distance travelled = 60 m
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