Question

3. A motor cycle moving with a speed of 5m/s if applied an acceleration of 0.2m/s2. Calculate the speed of motorcycle after 10 seconds, and the distance travelled by it in this time.

Answer 1

u = 5 m/s
a = 0.2 m/s²
t = 10 seconds
v = u + at
= 5 + 0.2×10
= 5+2
= 7 m/s
s = ut + 1/2at²
= (5×10) + (1/2)×(2/10)×(10×10)
= 50 + 10
= 60 m
Final speed = 7 m/s
Distance travelled in 10 seconds = 60 m

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Answer 2

u=5m/s, a=0.2m/s^2, t=10s. (given)

v=u+at

v=5+.2×10

v= 5+2

v= 7m/s

v^2=u^2+2as

(7)^2 = (5)^2 + 2 ×. 2×s

49 = 25  + .4s

49 - 25 = .4s

24 = .4s

s=24/.4

s=240/4

s= 60 m

distance travelled = 60 m