3. A number when successively divided by 1, 5 and 8 leaves remainders 1, 4 and 7 respectively.
Find the respective remainders if the order of divisors be reversed.
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Step-by-step explanation:
The no would be 79 as lcm of 1,5,8=40
and 40*n times - 1 will leave reminder as 1,4,7
thus 79/1 reminder will be 0 or 1 which becomes 0 ahead. 79/5 reminder will be 4 and 79/8 reminder will be 7
after interchanging the divisor
the reminders will be same but order is reversed that is previously it was 1,4,7
now after reversing divisor the reminder will be
7,4,1
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