Question

3. A parallel-plate capacitor consists of 26 metal strips,each of 3 cm x 4 cm, separated by mica sheets ofdielectric constant 6 and uniform thickness 0.2 mm.Find the capacitance.​

Answer 1

Answer:7.97×10⁹

Explanation:

Answer 2

Given:

Number of parallel capacitors = 26

dimensions of capacitors = 3cm×4cm

dielectric constant = 6

thickness = 0.2mm

To find:

Capacitance

Solution:

Arrangement of n parallel metal plate capacitor separated by a dielectric acts as a parallel combination of (n-1) capacitors.

so formula used to find capacitance is,

$C= \frac{(n-1)\kappa \varepsilon _{0} A}{d}$

here, n = no. of capacitors

         κ = dielectric constant

         A = area = length × breadth

         d = thickness

so putting all the values, we get

$C= \frac{(26-1)\times 6 \times 8.85 \times 10^-^1^2 \times 3 \times 4 \times 10^-^4 }{0.2 \times 10^-^3}$

C = 7.97 × 10⁻⁹ F

So, the capacitance will be 7.97 × 10⁻⁹ F.