Question

3.) A particle is moved from (0,0) to (a, a) under a force
F=(3i+ 4 j) from two paths. Path 1 is OP and path 2 is
OQP. Let W, and W, be the work done by this force in
these two paths. Then,
P(a, a)
5
45°
о
300Q
ta) W1 =W2
(b) W1 = W2, (c)W1 = 2W, (d) W1 = 2W​

Answer 1

Answer:

Option A

Explanation:

Work done = force*displacement

And magnitude of force is 5N.

For path 1,

Displacement is √2a units.(45-45-90 ∆)

So,

W1= 5*(√2a)

W1=5a√2

and

for path 2,

No matter how much distance it travels, displacement is same.

so, W1=W2

Answer 2

Answer:

W1=W2

Explanation:

No matter which path is taken,since the initial and final points are same then the work done would be same