x=t3+1/t2 diffrentation
Answers
Answered by
1
Suppose we wish to find dy
dx
when x = cost and y = sin t.
We differentiate both x and y with respect to the parameter, t:
dx
dt
= − sin t
dy
dt
= cost
From the chain rule we know that
dy
dt
=
dy
dx
dx
dt
so that, by rearrangement
dy
dx
=
dy
dt
dx
dt
provided dx
dt
is not equal to 0
So, in this case
dy
dx
=
dy
dt
dx
dt
=
cost
− sin t
= −cott
dx
when x = cost and y = sin t.
We differentiate both x and y with respect to the parameter, t:
dx
dt
= − sin t
dy
dt
= cost
From the chain rule we know that
dy
dt
=
dy
dx
dx
dt
so that, by rearrangement
dy
dx
=
dy
dt
dx
dt
provided dx
dt
is not equal to 0
So, in this case
dy
dx
=
dy
dt
dx
dt
=
cost
− sin t
= −cott
Similar questions