3. A particle is undergoing simple harmonic motion on
a straight line of amplitude 1 cm and time period
8 second. Starting from mean position the distance
covered by the particle in first five seconds is
approximately
Answers
Answered by
1
Answer:
i it helps you
Explanation:
x=Asinωt
x(t=1s)=Asin(
T
2π
t)=Asin(
8
2π
)=Asin(
4
π
)=
2
A
x(t=2s)=Asin(
T
2π
t)=Asin(
8
2π
×2)=Asin(
2
π
)=A
And the required ratio is:
x(t=2s)−x(t=1s)
x(t=1s)
=
A−
2
A
2
A
=
2
−1
1
=
2
+1
Answered by
0
Answer:
Explanation:
A= 1 cm
ω=2π/T
T= 8 sec
t= 5 sec
x=A sinωt
=1 × sin(2π/8) × 5
= sin 5π/4
= - 1/√2 cm
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