Question

A 1-0 kg box is moving across a rough floor with the roughness different at different places, which can be described by a position-dependent coefficient of kinetic friction. For a box moving along the x-axis, the coefficient of kinetic friction is the following function of x, where x is in m: µ(x) = 0,02 + 0,08·x. Find the work done by the kinetic frictional force on the box when it has moved (a) from x = 0 to x = 3 m, and (b) from x=3 m to x=6 m (g=10 m∙s-2).

Answer 1

Answer:

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Explanation:

A 1-0 kg box is moving across a rough floor with the roughness different at different places, which can be described by a position-dependent coefficient of kinetic friction. For a box moving along the x-axis, the coefficient of kinetic friction is the following function of x, where x is in m: µ(x) = 0,02 + 0,08·x. Find the work done by the kinetic frictional force on the box when it has moved (a) from x = 0 to x = 3 m, and (b) from x=3 m to X=6 m (g=10 m∙s-2).