3. A rectangular field has 80 m length and 48 m breadth. Three roads, each of width 2 m pass through the field such that two roads are parallel to the breadth and the third road parallel to the length. Find the area covered by the three roads.
Please solve this answer if the answer is correct I will mark it brainlist.
Answers
Answer:
The answer for this question is 344 m^2
Step-by-step explanation:
We know that width of each road is 2m.
Length of two of the roads (parallel to the breadth) = breadth = 48m.
Length of one road (parallel to the length) = length = 80m.
i] Area of two roads parallel to the breadth = 2(width * breadth)
= 2( 2*48)
= 2(96)
= 192 m. square
ii] Area of road parallel to the length = width of road * length
= 2 * 80
= 160 m. square
Now, subtract the areas common in both the roads :
We can see that the length and breadth of these common areas is 2 m.
Areas of the common part = (2*2) + (2*2)
= 4 + 4
= 8 m. square
Upon subtracting these from the total area of the roads :
(192 + 160) - 8
344 m. square
The area covered by the three roads is 344 m. square.
