Math, asked by shoebabano786, 9 months ago

3) A rhombus has diagonals that measure 6 cm
and 8 cm. What is its area? How much does
each side measure?​

Answers

Answered by jaggaiaherpa
0

Answer:

The area of a rhombus can be defined as the amount of space enclosed by a rhombus in a two-dimensional space. To recall, a rhombus is a type of quadrilateral projected on a two dimensional (2D) plane, having four sides that are equal in length and are congruent. It is also known as equilateral quadrilateral because all its four sides are equal in nature.

Answered by anuradhadevi2021
2

\huge{Answer}

The area of a rhombus can be found by using the formula:

A = (1/2)(d1)(d2)

Area = (1/2)(8)(6)

Area = 24 cm^2

Your other option is to remember that in a rhombus the diagonals bisect each other, and form right triangles. So you have 4 right triangles each with sides of 4 cm (1/2 of 8 cm) and 3 cm (1/2 of 6 cm). 4 x [(1/2) x (4)(3)] = 4 x 6 = 24 cm^2.

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