Question

A sells a bicycle to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays Rs. 225 for it, the cost price of the bicycle for A is?​

Answer 1

Step-by-step explanation:

Let cost price for A = Rs. 100.

SP for A = CP for B = 100 + 20% of 100 = 120.

SP for B = CP for C = 120 + 25% of 120 = 150.

Given,

CP for C = 225

So,

150 = 225

1 = 225/150

100 = (225 *100)/150 = Rs. 150.

CP for A = Rs. 150.

Note: You can solve this question by taking CP of A = X as well.

Answer 2

✪ᴀɴsᴡᴇʀ✪

• CP of Bicycle for A is Rs. 150.

★ᴇxᴘʟᴀɪɴᴀᴛɪᴏɴ★

Here,

$\:\:\:\:\: CP\:of\:C = Rs.225$

Since CP of C is SP of B,

$\implies SP\:of\:B = Rs. 225$

$\implies (CP + Profit)\:of\:B = Rs.225$

Since B sell at 25% profit,

$\:\:\:\:\: (CP + 25\%CP)\:of\:B = Rs. 225$

$\implies (CP + \frac{25}{100}CP)\:of\:B = Rs. 225$

$\implies (CP + \frac{CP}{4})\:of\:B= Rs. 225$

$\implies \frac{(4+1)CP}{4} \:of\:B = Rs. 225$

$\implies \frac{5CP}{4}\:of\:B = Rs. 225$

$\implies CP\:of\:B = Rs. 225\times \frac{4}{5}$

$\implies CP\:of\:B = Rs. 180$

Since CP of B is SP of A

$\implies SP\:of\:A = Rs. 180$

$\implies (CP + Profit)\:of\:A= Rs. 180$

Since A sells at 20% profit,

$\:\:\:\:\: (CP + 20\%CP)\:of\:A= Rs. 180$

$\implies (CP + \frac{20}{100}CP)\:of\:A= Rs. 180$

$\implies (CP + \frac{CP}{5})\:of\:A= Rs. 180$

$\implies \frac{(5+1)CP}{5}\:of\:A= Rs. 180$

$\implies \frac{6CP}{5}\:of\:A= Rs. 180$

$\implies CP\:of\:A= Rs.180\times \frac{5}{6}$

$\implies CP\:of\:A= Rs.30\times 5$

$\implies CP\:of\:A= Rs.150$