Question

3. A solid cylinder of height h,
cross sectional area A and
density 1.40 x 1000 kg /m*m*m
is immersed completely in
a mixture of liquid such
that it floats with its axis
vertical at the liquid-liquid
interface with length 3h/4
in lesser dense liquid as shown in the figure.
The lesser dense liquid is open to atmospheric
pressure P. If the density of lesser dense liquid is
1.0 x10 kg m, then the density of denser liquid will be
A. 1.5 * 10 kg m B. 2.0 10 kg m ?
e. 2.6 x 10 kg m D. 3.2 x 103 kg m-3
​

Answer 1

Answer:2.6*10³ kg/m³

Explanation:see the pic attached by me

Answer 2

The density of denser liquid will be dl2 = 2.6 x 10^3 kg/m^3.

Explanation:

Cross sectional area of cylinder = A

Density of cylinder = 1.40 x 1000 kg / m^3

V(im) / V to = do / dl

do = dl [ V(im)/V(to) + dl2 [V (im2) / Vto ]

1.4 = 1 (3/4) +x (1/4)

14/10 -3/4 = x / 4

4 ( 28 - 25)/ 20 = x

x = dl2 = 18/5 = 2.6 x 10^3 kg/m^3

dl2 = 2.6 x 10^3 kg/m^3

Hence the density of denser liquid will be dl2 = 2.6 x 10^3 kg/m^3.

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