Question

3. A system consists of 3 objects M1, M2 and M3 as shown in the diagram below. Consider the coefficient of kinetic friction between the block and surface to be 0.256. Calculate,
i. The friction force on the system
ii. The normal force
iii. The acceleration of the system
iv. In which direction will the system move.

Answer 1

Explanation:

For the motion of horizontal block, (m

2

+m

3

)a=T−f

2

−f

3

or (m+m)a=T−μmg−μmg

or 2ma=T−2μmg....(1)

For the motion of vertical block, m

1

a=m

1

g−T or ma=mg−T...(2)

From (1) and (2), 2ma=mg−ma−2μmg

or 3a=g−2μg

or a=

3

g(1−2μ)

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