3. A train having 50 wagons of 25 ton each is
moving with uniform velocity of 54 km/h.
Find the horse power developed, if the average
frictional force acting is 10N per ton.
Answers
Answer:
The horse power developed by the engine is 187500 watts.
Explanation:
Let the force per ton that is the frictional force be F.
So, F = 10 N
Number of wagons = 50.
Weight of each wagon = 25.
So, Total weight of the wagons = 50 × 25 = 1250 tonnes
The force of friction for 1250 tonnes = 1250 × 10 = 12500 N
The uniform velocity of the train = 54 km/h
= 54 × (5 / 18 ) m/s
= 15 m/s
The horse power developed by the engine = Force × velocity
= 12500 × 15
= 187500 watts.
Answer:
Given:
mass of train= 50 ×25= 1250N
total force = 10 per ton
= 10×1250 =12500N
uniform velocity = 54kmh
=54×1000/60×60 = 15ms
Explanation:
Power = Force × distance
=12500 ×15
= 187500
In horsepower
1 hp = 745.669
= 1/745.669 ×187500
= 251.4