Question

3. A trolley, while going down an
inclined plane,
has an
acceleration of 2 cm s2. What will
be its velocity 3 s after the start​

Answer 1

Answer:

6cm s^-1

explanation:

given velocity=0

time=3s

acceleration=2cm s^2

from first equation of motion

v = 0+2×3

v = 6cm s^-1

Answer 2

Given :-

Acceleration of trolley = 2 cm/s

Time taken by trolley = 3 sec

To Find :-

The final velocity after 3 seconds.

Analysis :-

Here we are given with the acceleration, time taken, initial velocity of the trolley.

In order to find the final velocity substitute the given values in the questions using the formula of first equation of motion.

Solution :-

We know that,

• u = Initial velocity
• t = Time
• v = Final velocity
• a = Acceleration

Using the formula,

$\underline{\boxed{\sf First \ equation \ of \ motion=v=u+at}}$

Given that,

Initial velocity (u) = 0 m/s

Time (t) = 3 sec

Acceleration (a) = 2 cm/s = 0.02 m/s²

Substituting their values,

⇒ v = 0 + 0.02 × 3

⇒ v = 0.02 × 3

⇒ v = 0.06 m/s

Therefore, the final velocity of trolley is 0.06 m/s.