3. A two-digit number is 3 more than 4 times the sum of its digits. If 18 is added to the number, it's digits are reversed. Find The Number.
Answers
Answer:
Let the unit digit be 'x'.
And let the ten's digit be 'y'.
And let the ten's digit be 'y'.So, the two digit number will be 10y+x
And let the ten's digit be 'y'.So, the two digit number will be 10y+xAccording to question,
And let the ten's digit be 'y'.So, the two digit number will be 10y+xAccording to question,(10y+x)-4(x+y)=3\\\\10y+x-4x-4y=3\\\\6y-3x=3\\\\2y-x=1-------------(1)
And let the ten's digit be 'y'.So, the two digit number will be 10y+xAccording to question,(10y+x)-4(x+y)=3\\\\10y+x-4x-4y=3\\\\6y-3x=3\\\\2y-x=1-------------(1)If 18 is added to the number, the digit are reversed.
And let the ten's digit be 'y'.So, the two digit number will be 10y+xAccording to question,(10y+x)-4(x+y)=3\\\\10y+x-4x-4y=3\\\\6y-3x=3\\\\2y-x=1-------------(1)If 18 is added to the number, the digit are reversed.So, it becomes,
And let the ten's digit be 'y'.So, the two digit number will be 10y+xAccording to question,(10y+x)-4(x+y)=3\\\\10y+x-4x-4y=3\\\\6y-3x=3\\\\2y-x=1-------------(1)If 18 is added to the number, the digit are reversed.So, it becomes,18+10y+x=10x+y\\\\18=10x-x+y-10y\\\\18=9x-9y\\\\2=x-y----------(2)
And let the ten's digit be 'y'.So, the two digit number will be 10y+xAccording to question,(10y+x)-4(x+y)=3\\\\10y+x-4x-4y=3\\\\6y-3x=3\\\\2y-x=1-------------(1)If 18 is added to the number, the digit are reversed.So, it becomes,18+10y+x=10x+y\\\\18=10x-x+y-10y\\\\18=9x-9y\\\\2=x-y----------(2)From eq(1) and (2), we get that
And let the ten's digit be 'y'.So, the two digit number will be 10y+xAccording to question,(10y+x)-4(x+y)=3\\\\10y+x-4x-4y=3\\\\6y-3x=3\\\\2y-x=1-------------(1)If 18 is added to the number, the digit are reversed.So, it becomes,18+10y+x=10x+y\\\\18=10x-x+y-10y\\\\18=9x-9y\\\\2=x-y----------(2)From eq(1) and (2), we get that2y-x=1\\\\-y+x=2\\\\----------------------------------------\\y=3\\\\and\ x-y=2\\\\x-3=2\\\\x=2+3\\\\x=5
And let the ten's digit be 'y'.So, the two digit number will be 10y+xAccording to question,(10y+x)-4(x+y)=3\\\\10y+x-4x-4y=3\\\\6y-3x=3\\\\2y-x=1-------------(1)If 18 is added to the number, the digit are reversed.So, it becomes,18+10y+x=10x+y\\\\18=10x-x+y-10y\\\\18=9x-9y\\\\2=x-y----------(2)From eq(1) and (2), we get that2y-x=1\\\\-y+x=2\\\\----------------------------------------\\y=3\\\\and\ x-y=2\\\\x-3=2\\\\x=2+3\\\\x=5So, the number will be
And let the ten's digit be 'y'.So, the two digit number will be 10y+xAccording to question,(10y+x)-4(x+y)=3\\\\10y+x-4x-4y=3\\\\6y-3x=3\\\\2y-x=1-------------(1)If 18 is added to the number, the digit are reversed.So, it becomes,18+10y+x=10x+y\\\\18=10x-x+y-10y\\\\18=9x-9y\\\\2=x-y----------(2)From eq(1) and (2), we get that2y-x=1\\\\-y+x=2\\\\----------------------------------------\\y=3\\\\and\ x-y=2\\\\x-3=2\\\\x=2+3\\\\x=5So, the number will be10y+x\\\\=10\times 3+5\\\\=30+5\\\\=35
Hence, the number will be 35.
Step-by-step explanation:
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