Question

3. A verandah 1.25 m wide is constructed all along the outside of a room 5.5 m long and 4 m wide. Find
the cost of cementing the floor of this verandah at the rate of 15 per sq m.
rea of​

Answer 1

Step-by-step explanation:

$\bold{Area \: of \: the \: room \: is \: given \: by \: 7.5 m\times 5m = 37.5 {m}^{2} }$

Area of the Verandah with room is given by

$\bold{(7.5 + 1.25 + 1.25)m \times (5 + 1.25 + 1.25)m}$

$\bold{\implies \: 10m \times 7.5m = 7 5{m}^{2}}$

$\bold{ \therefore \: the \: area \: of \: verandah \: =75 {m}^{2} - 35 {m}^{2} = 37.5 {m}^{2} }$

$\bold{cost \: of \: cementing \: the \: floor \: of \: verandah \implies \: rs.15 /{m}^{2} }$

$\bold{total \: cost \: of \: cementing \: the \: floor \: of \: the \: verandah}$

$\bold{ \implies{37.5 \times 15 = rs.562.5}}$

Answer 2

Total cost of cementing 450rps.

Given that,

Area of the room is 4×5.5=22m²

Area of the verandah with room is =(5.5+1.25+1.25)×(4+1.25+1.25)

8×6.5=52

Area of verandah 52−22

=30m²

Cost of cementing =15rps

Total cost of cementing =30×15

=450rps

Thus,

We get total cost of cementing 450rps.