Question

3. A wooden toy is in the form of a cone
surmounted on a hemisphere. The diameter
of the base of the cone is 6cm and height
is 4cm. Find the cost of painting the toy at
the rate of a 5 per sq m?​

Answer 1

Answer:

Total surface area of the toy = 2πr2+πrl

Total surface area of the toy = 2πr2+πrl=2×722×64+722×8×17cm2          [∵l=r2+h2=64+225=17cm]

Total surface area of the toy = 2πr2+πrl=2×722×64+722×8×17cm2          [∵l=r2+h2=64+225=17cm]=722×8(16+17)cm2=722×8×33cm2

Total surface area of the toy = 2πr2+πrl=2×722×64+722×8×17cm2          [∵l=r2+h2=64+225=17cm]=722×8(16+17)cm2=722×8×33cm2∴ Required cost = Rs.1007×722×8×33=Rs.58.08

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