Question

3. a) Write the sequence got by adding one to the square of consecutive natural numbers starting from 1
b) What is the 10th term of this sequence? c) Write the algebraic form of this sequence?

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Answer 1

A)

Step-by-step explanation:

B)Step-by-step explanation:

1)The 1st 3 terms in an arthematic sequence are a,a+d,a+2d where a is 1st term and d is common difference.so the three terms are 10,10+3,10+2*3= 10,13,16.

2) nth term of arthematic sequence is a+(n-1)d

so let a+(n-1)d=100

10+(n-1)3=100

3n-3=90

3n=93

n=31

so we can say that 100 is the term of arthematic sequence.

3)nth term of arthematic sequence is a+(n-1)d

so nth term of this sequence is 10+3(n-1)

=10+3n-3

=7+3n

4)Yes. Because 45 is a multiple of 3. Like nd is a multiple of d.

5)Let a+(n-1)d=181

10+(n-1)3=181

7+3n=181

3n=174

n=58

So 181 is 58th term of the arthematic sequence.

hope this helps...

Answer 2

Answer:

1)The 1st 3 terms in an arthematic sequence are a,a+d,a+2d where a is 1st term and d is common difference.so the three terms are 10,10+3,10+2*3= 10,13,16.

2) nth term of arthematic sequence is a+(n-1)d

so let a+(n-1)d=100

10+(n-1)3=100

3n-3=90

3n=93

n=31

so we can say that 100 is the term of arthematic sequence.

3)nth term of arthematic sequence is a+(n-1)d

so nth term of this sequence is 10+3(n-1)

=10+3n-3

=7+3n

4)Yes. Because 45 is a multiple of 3. Like nd is a multiple of d.

5)Let a+(n-1)d=181

10+(n-1)3=181

7+3n=181

3n=174

n=58

So 181 is 58th term of the arthematic sequence.

Step-by-step explanation:

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