Math, asked by velayatuaniruthuda, 4 months ago

3(−ab3+2ab2−3ab+2)−2(5ab3−6ab2+10ab)

Answers

Answered by pulakmath007
6

SOLUTION

TO EVALUATE

 \sf{3( - a {b}^{3}  + 2a {b}^{2}  - 3ab + 2) - 2( 5a {b}^{3}   -  6a {b}^{2}  + 10ab)}

EVALUATION

 \sf{3( - a {b}^{3}  + 2a {b}^{2}  - 3ab + 2) - 2( 5a {b}^{3}   -  6a {b}^{2}  + 10ab)}

 \sf{ = ( -3 a {b}^{3}  + 6a {b}^{2}  - 9ab + 6) - ( 10a {b}^{3}   -  12a {b}^{2}  + 20ab)}

 \sf{ = -3 a {b}^{3}  + 6a {b}^{2}  - 9ab + 6 - 10a {b}^{3}    +  12a {b}^{2}   -  20ab}

 \sf{ = -13 a {b}^{3}  + 18a {b}^{2}  - 29ab + 6 }

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Answered by atharva20kaushal
1

Answer:3(−ab3+2ab2−3ab+2)−2(5ab3−6ab2+10ab)

Step-by-step explanation:3(−ab3+2ab2−3ab+2)−2(5ab3−6ab2+10ab)3(−ab3+2ab2−3ab+2)−2(5ab3−6ab2+10ab)

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