3 acceleration, 87. A velocity of magnitude 40 m/s is directed at an angle of 40° East of North. Draw a vector on paper to represent this velocity Secourt travels 3 Em due North, then 5 km Fast Rene ac m (
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Answer:
Displacement of car =75
j
^
(75 km north)
−60cos45
i
^
+60sin45j (60 km north-west)
+20↑ (20 km east)
∴ Final location =(
2
−60
+20)↑+(
2
60
+75)
j
^
=(−60×0.7+20)↑+(42+75)
j
^
=−22↑+117
j
^
displacement =
(117)
2
+(22)
2
=
14173
=119 km.
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