Math, asked by kinjalkariya1998, 6 hours ago

3) Amit took a loan of Rs. 80,000 from a bank. If the rate of interest is 10% per annum find the difference in amounts he would be paying after 1 1 2 years if the interest is a) Compounded annually. b) Compounded half yearly.​

Answers

Answered by seebaluckyovan
0

Answer: (i) Given,

Principal amount, P = Rs80000

Rate of interest, R = 10% p.a.

Time period = 1 and a half years.

We know, Amount when interest is compounded annually, A =

A = P(1 + R/100)^n

Now, For the first year, A =

         A = 80000(1 + 10/100)^1 = Rs88000

For the next half year, this will act as the principal amount.

therefore Interest for 1/2 year at 10% p.a =  

             = (88000 x 1/2 x 10)/100 = Rs4400  

Required total amount = Rs (88000 + 4400) = Rs92400

(ii) If it is compounded half yearly, then there are 3 half years in 1 and a half years.

      therefore n = 3 half years.

And, Rate of interest = half of 10% p.a = 5% half yearly

therefore A = 80000 (1 +5/100)^3 = Rs92610  

therefore The difference in the two amounts = Rs (92610 - 92400) = Rs 210

Step-by-step explanation:

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