3 ampire current is passing through wire in 5 second . what will be the number of electron through that cross section area.
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Answer:
9 × 10¹⁹
Explanation:
q= I × T
= 3 × 5
= 15 C
N0W,
We know that 1 C HAS 6 × 10¹⁸ Electrons
so,
15 c has
15 × 6 × 10¹⁸
= 90 × 10¹⁸
= 9 × 10¹⁹ ELECTRONS
(if you didn't understand i mean to say that first calculate coulomb which in his case is 15 than multiply coulomb with 6 × 10 ¹⁸ and you'll get the answer which is 9 × 10¹⁹ ) i hope it helped you pls mark it as brainliest
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