Question

How to write a program to print the sum of the following series:
s=(1+2)/(1*2)+(1+2+3)/(1*2*3)+ - - - - - - upto n terms in java using bluej.​

Answer 1

Answer:

This is the required program for the question in Java:

import java.util.*;

public class Sum  {

   public static void main(String args[])   {

       int n,i;

       float s=0.0f,p=1.0f,q=1.0f;

       Scanner sc=new Scanner(System.in);

       System.out.print("Enter limit - ");

       n=sc.nextInt();

       sc.close();

       for(i=2;i<=n+1;i++) {

           q+=i;

           p*=i;

           s+=q/p;

       }

       System.out.println("Sum is: "+s);

   }

}

Note: Here, p calculates the values of denominator part and q calculates the value of numerator part of each term in the series. Then, the value of q/p is added to the sum variable. The sum is displayed on the screen after calculation.

Answer 2

=> Input : n = 4

=> Output : 3.91667

=> Series : (1 / 1) + (1 + 2) / (1 * 2) + (1 + 2 + 3) / (1 * 2 * 3) + (1 + 2 + 3 + 4) / (1 * 2 * 3 * 4) = 1 / 1 + 3 / 2 + 6 / 6 + 10 / 24 = 3.91667

=> Input : n = 6

=> Output : 4.07083

=> Series : (1 / 1) + (1 + 2) / (1 * 2) + (1 + 2 + 3) / (1 * 2 * 3) + (1 + 2 + 3 + 4) / (1 * 2 * 3 * 4) + (1 + 2 + 3 + 4 + 5) / (1 * 2 * 3 * 4 * 5) + (1 + 2 + 3 + 4 + 5 + 6) / (1 * 2 * 3 * 4 * 5 * 6)

=> 1 / 1 + 3 / 2 + 6 / 6 + 10 / 24 + 15 / 120 + 21 / 720

=> 4.07083

I hope this will help you dear..

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