Question

3. An element X has the following isotopic
composition :
200X = 90% , 199X = 8.0%, 202X = 2.0%
The average atomic mass of the natu-
rally occurring element X is closest to :
(A) 199 amu (B) 200 amu
(C) 201 amu
(D) 202 amu

explain with solution​

Answer 1

Answer:

option A: 199 amu

Explanation:

Average atomic mass =

(A1 x X1 + A2 x X2 + A3 x X3) /3 x 100

A= Isotopic mass

X= Percentage of occurance

Average atomic mass =

(200 x 90 +199 x 8+ 202 x 2) /3 x 100

Average atomic mass = 199.6 amu

HOPE THIS HELPS YOU

¶ THANK YOU ¶

PLEASE MARK AS BRAINLIEST.