Question

3. An elevator descends into a mine shaft at the rate of 6m/min. If the descent starts from 10m above the
ground level, how long will it take to reach - 350 m deep from the ground?​

Answer 1

Step-by-step explanation:

as it is 10 m above the ground..

therefore..total distance to be travelled is 350+10=360m

s=v×t

so t=360/6

=60