Question

3. An object 5 cm in length is placed at a distance of 20 cm in front of a convex mirror, it's image is formed at 10 cm behind the mirror. Find the nature and size of the image.


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Answer 1

Formula:$\frac{1}{v} + \frac{1}{u} + \frac{1}{f}$

▪️1(−20)1=151

▪️v1=607⇒v=760

▪️v=8.57≈8.6cm

▪️The image is formed behind the mirror at a distance of 8.6 cm ▪️m=h1h2=−uv

▪️→5h2=−208.57

▪️∴h2=2.175 cm

▪️Thus the image is 2.175 cm high, virtual and erect.▪️

Hence, this is the answer.

Hopes it help you✌️✌️

Answer 2

Answer:

Formula:\frac{1}{v} + \frac{1}{u} + \frac{1}{f}

v1 + u1+ f1

️1(−20)1=151

v1=607⇒v=760

️v=8.57≈8.6cm

The image is formed behind the mirror at a distance of 8.6 cm ▪️m=h1h2=−uv

️→5h2=−208.57

️∴h2=2.175 cm

️Thus the image is 2.175 cm high, virtual and erect.

Hence, this is the answer