Question

3. An SUV is traveling at a speed of 18 m/s. If the SUV has a mass of 1,550 kg, what force must be applied to stop it in 8 seconds?

A. –2.25 N
B. –4,030.7 N
C. –2,700.0 N
D. –3,487.5 N

Answer 1

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Answer 2

answer is D

intial velocity (u) = 18 m/s

final velocity (v) = 0 m/s

therefore retardation (a) = (v-u)/t = (0-18)/8 = 18/8 m/s^2

therefore force = mass × retardation = 1550 × 18/8 = 3487.5 N

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