Question

√3 and -√3 are the zeroes of f(x) = x⁴-3x⁴-x²+9x-6.​

Answer 1

Answer:

-3x

Step-by-step explanation:

underroot 3 and underroot-3 are zeroes of the above equation.

The zeroes is (x+underroot3) (x-underroot 3)

(x^2-3) is zeroes of the given equation.

When we divide the above equation by (x^2-3).

We will get the value -3x.

HOPE YOU UNDERSTAND THIS

Answer 2

Answer:

✓3 and -✓3 are not the zeroes of f(x) = x⁴-3x⁴-x²+9x-6

Step-by-step explanation:

✓3 and -✓3 are only the zeroes of f(x) when f(✓3) and f(-✓3) = 0

=(✓3)⁴-3(✓3)⁴-(✓3)²+9(✓3)-6

=9-3×9-3+9✓3-6

=9-27-3-6+9✓3

=-27+9✓3

≠0

that's why ✓3 is not the zero of f(x)

=(-✓3)⁴-3(-✓3)⁴-(-✓3)²+9(-✓3)-6

=9-27-3-6-9✓3

=-27-9✓3

≠0