3 angles of triangle are in AP if smallest angle
is 40° then find the remaining angles
to By taking angles in orders
a+d, a+2d like that.
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40+40+d+40+2d=180 {Angle Sum Property}
3d=60
D=20
1st angle = 40
2nd angle=40+d=40+20=60
3rd angle=40+2d=40+40=80
3d=60
D=20
1st angle = 40
2nd angle=40+d=40+20=60
3rd angle=40+2d=40+40=80
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