3
Answer any TEN questions.
1.
Solve the equation r' + 6x + 20 = 0, one root being
1+ 3i.
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1
Answer:
Roots are: (1+3i),(1–3i),(−2)
Step-by-step explanation:
Sum of the roots = a+1+3i+1−3i=− Coefficient of x2=0
=>a+2=0=>a=−2
Product of the roots = (a)(1+3i)(1–3i)=− Coefficient of x^0 or (−1)∗ Constant
=>a(1−9i2)=−20=>a(10)=−20
=>a=−2
Roots are: (1+3i),(1–3i),(−2)
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