Question

3
Answer any TEN questions.
1.
Solve the equation r' + 6x + 20 = 0, one root being
1+ 3i.​

Answer 1

Answer:

Roots are: (1+3i),(1–3i),(−2)

Step-by-step explanation:

Sum of the roots = a+1+3i+1−3i=−  Coefficient of  x2=0  

=>a+2=0=>a=−2  

Product of the roots = (a)(1+3i)(1–3i)=−  Coefficient of x^0 or  (−1)∗ Constant

=>a(1−9i2)=−20=>a(10)=−20  

=>a=−2

Roots are: (1+3i),(1–3i),(−2)