3. Area of a square field is 3600m2. A rectangular field whose length is twice its width has
perimeter equal to perimeter of square field. Find the area rectangular field. (3200m)
Answers
Answer:
3200m²
Step-by-step explanation:
Given :
i) Area of a square field(A1) = 3600m²
ii) Length of rectangle(l2) =2× breadth of rectangle (b2) l2 = 2 × b2
iii)Perimeter of rectangle(P2) = perimeter of square(P1)
To find : Area of rectangular field(A2)=?
Solution:
Area of a square field(A1) = 3600m²
(l1)²=3600m²
l1 = 60 m.....(1)
Perimeter of square (P1) = l1 ×4
=60×4
=240m........(2)
Thus,
Perimeter of rectangle(P2)=240m....(3)
Perimeter of rectangle(P2)= 2(l2+b2)
= 2(2b2+b2)
= 2(3b2)
=6b2
240=6b2
b2=40m.....(4)
l2 = 2×b2
= 2 ×40
=80 m.....(5)
Area of rectangular field = l2 × b2
= 80m × 40m
= 3200m².
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• Area of the square field is 3600 m².
• A rectangular field whose length is twice its width has perimeter equal to perimeter of square field.
• What's the area of the rectangular field?
Formula to be used :-
• Area of a square = a²
Where,
a = side
• Perimeter of a square = 4a
• Area of a rectangle = Width × Breadth
As per question :-
Given that,
Area of the square field = 3600 m²
Hence,
⟹ a² = 3600
⟹ a = 60
Then,
perimeter of the square filed
= 4a
= 4 × 60
= 240 m
________________________________________________
Let the length and breadth of the rectangular field be x m and y m respectively.
Given that,
A rectangular field whose length is twice its width.
Hence,
⟹ x = 2y.............. eq(1)
Again, it’s given that
A rectangular field whose length is twice its width has perimeter equal to perimeter of square field.
Therefore,
⟹ 2 ( x + y) = 240
⟹ x + y = 120............ eq(2)
Put x = 2y in eq(2)
⟹ x + y = 120
⟹ 2y + y = 120
⟹ 3y = 120
⟹ y = 40
Substituting y = 40 in eq(1)
x = 2y
⟹ x = 2 × 40
⟹ x = 80
Hence,
Width of the rectangular field is = 40 m
Breadth of the rectangular field is = 80 m
Therefore, area of the rectangular field is
= Width × Breadth
= 80 × 40
= 3200 m²
Hence, the area of the rectangular field is 3200 m².