Question

3 atoms of magnesium combine with 2 atoms of nitrogen what will be the weight of magnesium which combines with 1.86 of Nitrogen​

Answer 1

Answer:

Equation:

3Mg + N2 → Mg3N2

3mol Mg combines with 1mol N2.

Molar mass N2 = 28.014g/mol

1.86g N2 = 1.86/28.014 = 0.0664mol N2

This will require 0.0664*3 = 0.1992mol Mg

Molar mass Mg = 24.305g/mol

0.1992mol Mg = 24.305*0.1992 = 4.84g Mg required.

Answer 2

ANSWER:4.842

EXPLANATION:     let ''X'' g of Mg combines with 1.86 g of N

atomic mass of Magnesium=24.3 g

atomic mass of Nitrogen=14

Given,3 atoms of Mg combine with 2 atoms of N

so,    (24.3 × 3) g of Mg ⇒(14 × 2) g of N

                  (''X'')g of Mg ⇒(1.86) g of N

by solving this we get

                    X=1.86 x 24.3 x 3/ 2 x 14

                    X=67.797/14

                    X=4.842