Math, asked by aksharachinnari, 2 months ago

3
(b) 3(n-5) = 21
(e) 4(2-x) = 8
(c) 3(n-
5--21
(3) 2(x+4)= 12
(d) - 4(2+x)= 8
the following equations:
Sohe the following equations:​

Answers

Answered by niishaa
4

Answer:

b) 3(n-5) = 21

3n -15 = 21

3n = 21 +15

3n = 36

n = 36/3

n = 12

e) 4(2-x) = 8

8-4x = 8

-4x = 8-8

-4x = 0

x = 0/-4 = 0

x = 0

(3) 2(x+4) = 12

2x +8 = 12

2x = 12- 8

2x = 4

x = 4/2

x = 2

(d) -4(2+x) = 8

-8-4x = 8

-4x = 8+8

-4x = 16

x = 16/-4

x = -4

Answered by harshitha926594
2

Answer:

a) \:  2(x + 4) = 12 \\ 2x + 8 = 12 \\ 2x = 12 - 8 \\ 2x = 4 \\ x =  \frac{4}{2} \\ x =  \:  \underline{ \underline{2}} \\  \\ b) \: 3(n-5) = 21 \\ 3n - 15 = 21 \\ 3n = 21 + 15 \\ 3n = 36 \\ n =  \frac{36}{3}  \\ n =  \:  \underline{ \underline{12}} \\  \\ c) \: 3(n-5)-(-21) \\  = 3n - 15 + 21 \\  = 3n + 6 \\  =   \: \underline{ \underline{3(n + 2)}} \\  \\ d) \: - 4(2+x)= 8 \\    - 8 + ( - 4x) = 8 \\    - 8 - 4x = 8 \\  - 8 - 8 = 4x \\  \frac{ - 16}{4}  = x \\  \underline{ \underline{ - 4}} = x \\  \\ e) \: 4(2-x) = 8 \\ 8 - 4x = 8 \\ 8 = 8 + 4x \\ 8 - 8 = 4x \\  \frac{0}{4}  = x \\ \underline{ \underline{0}} = x

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